document.write( "Question 1084214: pattern:1/2;2/5;6/8;8/11\r
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Algebra.Com's Answer #698324 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Here are what I think are the first 10 terms:\r\n" );
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document.write( "1/2, 2/5, 6/8, 8/11, 15/14, 18/17, 28/20, 32/23, 45/26, 50/29,\r\n" );
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document.write( "The numerators 1, 2, 6, 8, 15, 18, 28, 32, 45, 50\r\n" );
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document.write( "follow this pattern:\r\n" );
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document.write( "1∙1, 2∙1, 3∙2, 4∙2, 5∙3, 6∙3, 7∙4, 8∙4, 9∙5, 10∙5,\r\n" );
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document.write( "The first factor of the numerators are just 1, 2, 3,...\r\n" );
document.write( "with the general term of simply n.\r\n" );
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document.write( "The second factors of the numerators are\r\n" );
document.write( "1, 1, 2, 2, 3, 3, 4, 4, 5, 5,\r\n" );
document.write( "The way to get the general term is by using the greatest integer\r\n" );
document.write( "function, also called the floor function of (n+1)/2 \r\n" );
document.write( "indicated by ë(n+1)/2û, the greatest integer not exceeding (n+1)/2\r\n" );
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document.write( "The denominators are 2,5,8,11,14,17,... with general term 3n-1\r\n" );
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document.write( "So the general (nth) term is: \r\n" );
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document.write( "an = n∙ë(n+1)/2û/(3n-1).\r\n" );
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document.write( "Edwin
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