document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084169>Question 1084169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Common radio of the following GP and the number of terms 10/7,1.…...343/1000 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698319 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10/7,1.…...343/1000 <BR>\n" );
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document.write( "common ratio = r = 1/(10/7) = 7/10<BR>\n" );
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document.write( "a(n) = a(1)*r^(n-1)<BR>\n" );
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document.write( "Solve for \"n\"::<BR>\n" );
document.write( "343/1000 = (10/7)*(7/10)^(n-1)<BR>\n" );
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document.write( "343/1000 = 1*(7/10)^(n-2)<BR>\n" );
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document.write( "(n-2)log(7/10) = log(343/1000)<BR>\n" );
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document.write( "n-2 = log(0.343)/log(0.7)<BR>\n" );
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document.write( "n-2 = 3<BR>\n" );
document.write( "Ans: n = 5<BR>\n" );
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