document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084223>Question 1084223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A special rubber ball is dropped from the top of a building 81m high. If after falling it bounces back to two-thirds of the previous bouncing height, then<BR>\n" );
document.write( "how high will it bounce the 5th time?What is the total distance it has covered the 6th time it touches the ground? Solve using Geometric Sequence </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698310 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a*r^(n-1) is height, with a=81, r=2/3 and n the number of times.<BR>\n" );
document.write( "81*(2/3)^4=81*16/81=16 feet on the fifth time.<BR>\n" );
document.write( "81 foot drop and hits 1 (81 feet)<BR>\n" );
document.write( "bounces back up 54 feet (2/3 of 81)<BR>\n" );
document.write( "drops 54 feet (189 feet distance) hits 2<BR>\n" );
document.write( "rises 36 feet (225 feet distance) and falls 36 feet to hit 3 (261 feet distance)<BR>\n" );
document.write( "rises 24 feet and falls 24 feet to hit 4 (309 feet distance)<BR>\n" );
document.write( "rises 16 feet and falls 16 feet to hit 5 (341 feet)<BR>\n" );
document.write( "rises 10 2/3 feet and falls 10 2/3 feet to hit 6 (362 1/3 feet). </SPAN>\n" );
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