document.write( "Question 95826: Find three consecutive odd integers such that three times the second minus the third is 11 more than the first.
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document.write( "I set the equation up as follows:
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document.write( "3(x + 2) - x + 4 = x + 11
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document.write( "Thanks for your help \n" );
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Algebra.Com's Answer #69831 by checkley71(8403) ![]() You can put this solution on YOUR website! 3(X+2)-(X+4)=X+11 \n" ); document.write( "3X+6-X-4=X+11 \n" ); document.write( "3X-X-X=11-6+4 \n" ); document.write( "X=9 ANSWER FOR THE SMALLEST NUMBER \n" ); document.write( "THE OTHER NUMBERS ARE 11 & 13. \n" ); document.write( "PROOF \n" ); document.write( "3*11-13=9+11 \n" ); document.write( "33-13=20 \n" ); document.write( "20=20 \n" ); document.write( " |