document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084190>Question 1084190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Medical research has concluded that people experience a common cold roughly two times per year.Assume that the time between colds is normally distributed with a mean of 160 days and a standard deviation of 40 days.                           a-what is the probability of going 200 or more days between colds ?                     b- what is the probabilty of going 365 or more days ?              c- what is the probability of going between 250 and 320 days?                        d- what is the probability of getting a cold within 80 days of a previous cold?           </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698298 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "> = (200-160)/40 which is > =+1 or 0.1587.<BR>\n" );
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document.write( ">=365 days is (365-160)/40=205/40=5.125 or <0.0001 (1.5 x 10^-7)<BR>\n" );
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document.write( "between 250 and 320 days is z between 2.25 and 4  or 0.0122<BR>\n" );
document.write( "<=(80-160)/40 or < = -2 or 0.0228<BR>\n" );
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