document.write( "Question 1084176: An ordinary (fair) die is a cube with the numbers
\n" ); document.write( "1
\n" ); document.write( " through
\n" ); document.write( "6
\n" ); document.write( " on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
\n" ); document.write( "Compute the probability of each of the following events:
\n" ); document.write( "Event
\n" ); document.write( "A
\n" ); document.write( ": The sum is greater than
\n" ); document.write( "9
\n" ); document.write( ".
\n" ); document.write( "Event
\n" ); document.write( "B
\n" ); document.write( ": The sum is divisible by
\n" ); document.write( "4
\n" ); document.write( ".
\n" ); document.write( "

Algebra.Com's Answer #698297 by Boreal(15235)\"\" \"About 
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The probabilities
\n" ); document.write( "sum is 2: 1/36
\n" ); document.write( "sum is 3: 2/36
\n" ); document.write( "(others omitting the denominator)
\n" ); document.write( "4:3
\n" ); document.write( "5:4
\n" ); document.write( "6:5
\n" ); document.write( "7:6
\n" ); document.write( "8:5
\n" ); document.write( "9:4
\n" ); document.write( "10:3
\n" ); document.write( "11:2
\n" ); document.write( "12:1
\n" ); document.write( "Therefore, greater than 9 is 6/36=1/6
\n" ); document.write( "Divisible (evenly, I assume) by 4, is 3,6,9,12, or 12/36=1/3
\n" ); document.write( "
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