document.write( "Question 1084201: please help me to solve that the polynomial {x^2-3} is irreducible over the field of rational numbers \n" ); document.write( "
Algebra.Com's Answer #698277 by rothauserc(4718)\"\" \"About 
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We use the fact that f(x) is irreducible over the field of rational numbers(Q) if and only if f(x+a) is irreducible for any a an element of Q.
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\n" ); document.write( "We prove that the polynomial f(x+1) is irreducible
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\n" ); document.write( "We have
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\n" ); document.write( "(x+1)^2 - 3 = x^2 +2x + 1 - 3 = x^2 +2x -2
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\n" ); document.write( "since the nonzero coefficient of highest degree is 1(x^2 term), f(x+1) is monic
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\n" ); document.write( "all the non-leading coefficients are divisible by the prime number 2(the 2x term)
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\n" ); document.write( "Eisenstein's Criterion\r
\n" ); document.write( "\n" ); document.write( "Suppose we have the following polynomial with integer coefficients.\r
\n" ); document.write( "\n" ); document.write( "P(x) = a(n)x^n + a(n−1)x(n−1) +...+ ⋯ + a(1)x + a(0)\r
\n" ); document.write( "\n" ); document.write( "If there exists a prime number p such that the following three conditions all apply:\r
\n" ); document.write( "\n" ); document.write( " p divides each a(i) for i not equal to n,
\n" ); document.write( " p does not divide a(n), and
\n" ); document.write( " p^2 does not divide a(0),\r
\n" ); document.write( "\n" ); document.write( "then Q is irreducible over the rational numbers
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\n" ); document.write( "Since the constant term is not divisible by 2^2, Eisenstein’s criterion implies that the polynomial f(x+1) is irreducible over Q
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\n" ); document.write( "Therefore by the fact stated above, the polynomial f(x) is also irreducible over Q.
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