document.write( "Question 1084185: Please list down all the possible subset of A={1,2,3} \n" ); document.write( "
Algebra.Com's Answer #698255 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your set is {1,2,3}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "one possible subset is {1,2,3}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that is called an improper subset.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in general, every set is an improper subset of itself.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the other possible subsets are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "{1} \n" ); document.write( "{2} \n" ); document.write( "{3} \n" ); document.write( "{1,2} \n" ); document.write( "{1,3} \n" ); document.write( "{2,3}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they are called proper subsets because the super set {1,2,3} contains at least 1 element that is not within the sub set.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "therefore, all possible subsets of {1,2,3} are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "{1} \n" ); document.write( "{2} \n" ); document.write( "{3} \n" ); document.write( "{1,2} \n" ); document.write( "{1,3} \n" ); document.write( "{2,3} \n" ); document.write( "{1,2,3}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they include all proper subsets plus the improper subset of {1,2,3}.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |