document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084182>Question 1084182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please answer -3,-1,1,3,5 using recursive formula </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698250 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you start with -3 and keep adding 2 to it, you will wind up with 5.\r<BR>\n" );
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document.write( "-3 +  = -1 + 2 = 1 + 2 = 3 + 2 = 5\r<BR>\n" );
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document.write( "your recursive formula would be A[n+1] = A[n] + 2\r<BR>\n" );
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document.write( "you would need a starting point, such as A[1] = -3\r<BR>\n" );
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document.write( "you would run your recursive program 4 times.\r<BR>\n" );
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document.write( "A[2] = A[1] + 2 = -3 + 2 = -1<BR>\n" );
document.write( "A[3] = A[2] + 2 = -1 + 2 = 1<BR>\n" );
document.write( "A[4] = A[3] + 2 = 1 + 2 = 3<BR>\n" );
document.write( "A[5] = A[4] + 2 = 3 + 2 = 5\r<BR>\n" );
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document.write( "your result would be A[5] = 5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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