document.write( "Question 1084174: Tanxsin^2x=1.21tanx \n" ); document.write( "
Algebra.Com's Answer #698245 by ikleyn(53765)\"\" \"About 
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document.write( "The only solution in the interval [\"0\",\"2pi\") are x= 0 ans x= \"pi\".\r\n" );
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document.write( "The solutions on the number line are x = \"k%2Api\", k = 0, +/-1, +/-2, . . . \r\n" );
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document.write( "The steps:\r\n" );
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document.write( "\"tan%28x%29%2Asin%5E2%28x%29\" = \"1.21%2Atan%28x%29\"  ====>\r\n" );
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document.write( "\"tan%28x%29%2Asin%5E2%28x%29+-+1.21%2Atan%28x%29\" = 0  ====>\r\n" );
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document.write( "\"tan%28x%29%2A%28sin%5E2%28x%29+-+1.21%29\" = 0.\r\n" );
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document.write( "The term (sin^2(x) - 1.21) is NEVER zero.\r\n" );
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document.write( "Therefore, the only solutions come from tan(x) = 0.\r\n" );
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