document.write( "Question 1084171: Please give the recursive formula in both subscript and function.
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Algebra.Com's Answer #698242 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "In subscript form, the recursive formula would be
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\n" ); document.write( "Which says \"The starting term is . To get the nth term , we need to multiply the previous term by -3.\"
\n" ); document.write( "In this case, n is some positive whole number (n > 0).\r
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\n" ); document.write( "\n" ); document.write( "With function form, we have the same basic format just with different notation
\n" ); document.write( "The function form would be
\n" ); document.write( "\"f%281%29+=+2\"
\n" ); document.write( "\"f%28n%29+=+-3%2Af%28n-1%29\"
\n" ); document.write( "where n > 0 is a whole number.\r
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\n" ); document.write( "\n" ); document.write( "If we plug in n = 2 to get the second term, we get
\n" ); document.write( "\"f%28n%29+=+-3%2Af%28n-1%29\"
\n" ); document.write( "\"f%282%29+=+-3%2Af%282-1%29\" replace every n with 2
\n" ); document.write( "\"f%282%29+=+-3%2Af%281%29\"
\n" ); document.write( "\"f%282%29+=+-3%2A%282%29\" Replace f(1) with 2 (since \"f%281%29+=+2\" is defined above)
\n" ); document.write( "\"f%282%29+=+-6\"
\n" ); document.write( "and we get the proper second term, which is -6\r
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\n" ); document.write( "\n" ); document.write( "If we plug in n = 3 to get the third term, we get
\n" ); document.write( "\"f%28n%29+=+-3%2Af%28n-1%29\"
\n" ); document.write( "\"f%283%29+=+-3%2Af%283-1%29\" replace every n with 3
\n" ); document.write( "\"f%283%29+=+-3%2Af%282%29\"
\n" ); document.write( "\"f%283%29+=+-3%2A%28-6%29\" Replace f(2) with -6 (since we just found \"f%282%29+=+-6\" above)
\n" ); document.write( "\"f%283%29+=+18\"
\n" ); document.write( "and we get the proper third term, which is 18\r
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\n" ); document.write( "\n" ); document.write( "The rest of the terms are generated in this recursive fashion.\r
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