document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084125>Question 1084125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Complete the square to write each function in f(x) = a(x-h)^2 + k form. Determine the vertex and the axis of symmetry of the graph of the function. Then plot several points to complete the graph. \r<BR>\n" );
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document.write( "f(x) = x^2 - x - 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698185 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2-x-6=0<BR>\n" );
document.write( "x^2-x=6<BR>\n" );
document.write( "x^2-x+1/4=6.25, add 1/4 to both sides.  Get 1/4 by taking half of the x term and squaring it. That will allow one to complete the square.<BR>\n" );
document.write( "(x-1/2)^2=6.25<BR>\n" );
document.write( "(x-(1/2))^2-6.25=0<BR>\n" );
document.write( "vertex is at (1/2, -6.25).  One takes the value of x and changes the sign and the constant at the end keeps the sign and is the y-value.<BR>\n" );
document.write( "axis of symmetry is at x=(1/2)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-x-6%2C%28x-0.5%29%5E2-6.25%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-x-6%2C%28x-0.5%29%5E2-6.25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  This plots both x^2-x-6 and (x-0.5)^2-6.25\r<BR>\n" );
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