document.write( "Question 95833: John invested a part of $50000 at the bank which has 4 1/2% interest rate and the other part at the bank which has 5 1/2% The former yields $ 750 more each year than the latter. How much did he invest at ezch bank with different interest rate? \n" ); document.write( "
Algebra.Com's Answer #69817 by checkley71(8403)\"\" \"About 
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.045X=.055(50000-X)+750
\n" ); document.write( ".045=2750-.055X+750
\n" ); document.write( ".045X+.055X=2750+750
\n" ); document.write( ".1X=3500
\n" ); document.write( "X=3500/.1
\n" ); document.write( "X=35000 AMOUNT INVESTED @ 4.5%.
\n" ); document.write( "50000-35000=15000 INVESTED @ 5.5%
\n" ); document.write( "PROOF
\n" ); document.write( ".045*35000=.055*15000+750
\n" ); document.write( "1575=825+750
\n" ); document.write( "1575=1575
\n" ); document.write( "
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