document.write( "Question 95840: The perimeter of a rectangle is 56cm. The width is 6cm less than the lenght. Find the width and the lenght \n" ); document.write( "
Algebra.Com's Answer #69813 by checkley71(8403)\"\" \"About 
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2L+2W=56
\n" ); document.write( "2L+2(L-6)=56
\n" ); document.write( "2L+2L-12=56
\n" ); document.write( "4L=56+12
\n" ); document.write( "4L=68
\n" ); document.write( "L=68/4
\n" ); document.write( "L=17 ANSWER FOR THE LENGTH.
\n" ); document.write( "W=17-6
\n" ); document.write( "W=11 ANSWER FOIR THE WIDTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*17=2*11=56
\n" ); document.write( "34+22=56
\n" ); document.write( "56=56
\n" ); document.write( "
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