document.write( "Question 95840: The perimeter of a rectangle is 56cm. The width is 6cm less than the lenght. Find the width and the lenght \n" ); document.write( "
Algebra.Com's Answer #69813 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2L+2W=56 \n" ); document.write( "2L+2(L-6)=56 \n" ); document.write( "2L+2L-12=56 \n" ); document.write( "4L=56+12 \n" ); document.write( "4L=68 \n" ); document.write( "L=68/4 \n" ); document.write( "L=17 ANSWER FOR THE LENGTH. \n" ); document.write( "W=17-6 \n" ); document.write( "W=11 ANSWER FOIR THE WIDTH. \n" ); document.write( "PROOF \n" ); document.write( "2*17=2*11=56 \n" ); document.write( "34+22=56 \n" ); document.write( "56=56 \n" ); document.write( " |