document.write( "Question 1084066: Please help me solve this problem:
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Algebra.Com's Answer #698120 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "         4t-6 = 24-t\r\n" );
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document.write( "We want only terms with letters on the left and terms without\r\n" );
document.write( "letters on the right.\r\n" );
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document.write( "So we begin by getting rid of the letter term -t on the right.\r\n" );
document.write( "So we add its opposite, +t, to both sides like this:\r\n" );
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document.write( "         4t-6 = 24-t\r\n" );
document.write( "         +t       +t      <--adding opposite +t to both sides\r\n" );
document.write( "        ------------\r\n" );
document.write( "         5t-6 = 24\r\n" );
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document.write( "Next we get rid of the term without a letter, -6, on the left.\r\n" );
document.write( "So we add its opposite, +6, to both sides like this: \r\n" );
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document.write( "         4t-6 = 24-t\r\n" );
document.write( "         +t       +t\r\n" );
document.write( "        ------------\r\n" );
document.write( "         5t-6 = 24\r\n" );
document.write( "           +6   +6      <--adding opposite +6 to both sides\r\n" );
document.write( "        -----------\r\n" );
document.write( "         5t   = 30\r\n" );
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document.write( "Now that we have only one term with a letter on the\r\n" );
document.write( "left and only one term without a letter on the right,\r\n" );
document.write( "we are ready to get rid of the number 5, the \r\n" );
document.write( "coefficient of the letter, by dividing:\r\n" );
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document.write( "         4t-6 = 24-t\r\n" );
document.write( "         +t       +t\r\n" );
document.write( "        ------------\r\n" );
document.write( "         5t-6 = 24\r\n" );
document.write( "           +6   +6\r\n" );
document.write( "        -----------\r\n" );
document.write( "         5t   = 30\r\n" );
document.write( "         \"%285t%29%2F5\"\"%22%22=%22%22\"\"30%2F5\"      <--dividing both sides by 5\r\n" );
document.write( "         \"%28cross%285%29t%29%2Fcross%285%29\"\"%22%22=%22%22\"\"6\"     <--canceling 5's on left, dividing on right\r\n" );
document.write( "          t   = 6      <--that's the solution.\r\n" );
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document.write( "Now we check our solution by substituting (6) for t in the \r\n" );
document.write( "original equation:\r\n" );
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document.write( "         4t-6 = 24-t\r\n" );
document.write( "       4(6)-6 = 24-(6)\r\n" );
document.write( "         24-6 = 24-6\r\n" );
document.write( "           18 = 18\r\n" );
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document.write( "Since we get the same number on the left and right, we know that\r\n" );
document.write( "the answer t = 6 is correct.\r\n" );
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document.write( "Edwin

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