document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083792>Question 1083792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For what value of k the line 2x-y+k=0 is tangent to the parabola y^2=6x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697846 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For what value of k the line 2x-y+k=0 is tangent to the parabola y^2=6x?<BR>\n" );
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document.write( "2y*dy = 6*dx<BR>\n" );
document.write( "dy/dx = 3/y = the slope of the parabola<BR>\n" );
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document.write( "The slope of 2x-y+k=0 is 2<BR>\n" );
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document.write( "3/y = 2<BR>\n" );
document.write( "y = 3/2;  x = 3/8<BR>\n" );
document.write( "The tangent point is (3/8,3/2)<BR>\n" );
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document.write( "2x-y+k=0<BR>\n" );
document.write( "3/4 - 3/2 + k = 0<BR>\n" );
document.write( "k = 3/4\r<BR>\n" );
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document.write( " </SPAN>\n" );
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