document.write( "Question 1083771: The hypotenuse of a right triangle is twice as long as one of the legs. If the other leg is the square root of 8, find the other leg. So I thought the problem would be set up as x^2 + square root of eight squared = 2x squared. but the answer after I work the problem is not correct. Please help! My second day on this problem! \n" ); document.write( "
Algebra.Com's Answer #697817 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "let the hypotenuse be \"c\",legs \"a\" and \"b\"\r
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\n" ); document.write( "\n" ); document.write( "in a right triangle: \"c%5E2=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "if the hypotenuse \"c\" of a right triangle is\"+twice+\"as long as one of the legs, let’s say \"a\", we have \"c=2a\"->\"a=c%2F2\"\r
\n" ); document.write( "\n" ); document.write( "if the other leg \"b=sqrt%288%29\", than we have:\r
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\n" ); document.write( "\n" ); document.write( "\"c%5E2=%28c%2F2%29%5E2%2B%28sqrt%288%29%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"c%5E2=c%5E2%2F4%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"c%5E2-c%5E2%2F4=8\"\r
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\n" ); document.write( "\n" ); document.write( "\"3c%5E2%2F4=8\"\r
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\n" ); document.write( "\n" ); document.write( "\"3c%5E2=8%2A4\"\r
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\n" ); document.write( "\n" ); document.write( "\"c%5E2=32%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"c=sqrt%2832%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"c=3.265986323710904\"\r
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\n" ); document.write( "\n" ); document.write( "\"c=3.27\"\r
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\n" ); document.write( "\n" ); document.write( "->\"a=c%2F2\"->\"a=3.27%2F2\"->\"highlight%28a=1.64%29\"->other leg\r
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\n" ); document.write( "\n" ); document.write( "\"b=sqrt%288%29\"->\"b=2.83\"\r
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\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2%2Bb%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%283.27%29%5E2=%281.64%29%5E2%2B%282.83%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"10.6929=2.6896%2B8.0089\"\r
\n" ); document.write( "\n" ); document.write( "\"10.6929=10.6985\".........round to one decimal place\r
\n" ); document.write( "\n" ); document.write( "\"10.7=10.7\"\r
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