document.write( "Question 1083721: Q1)if a sinēθ+b cosēθ =c
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document.write( "then prove that: tan θ=√c-b/a-c \n" );
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Algebra.Com's Answer #697769 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! if a*sin^2 + b*cos^2 = c \n" ); document.write( "then prove that: tan = sqrt((c-b)/(a-c)) \n" ); document.write( "------- \n" ); document.write( "a*sin^2 + b*cos^2 = c \n" ); document.write( "a*sin^2 + a*cos^2 + (b-a)*cos^2 = c \n" ); document.write( "a + (b-a)*cos^2 = c \n" ); document.write( "cos^2 = (a-c)/(a-b) \n" ); document.write( "======================== \n" ); document.write( "a*sin^2 + b*cos^2 = c \n" ); document.write( "a*sin^2 - b*sin^2 + b*cos^2 + b*sin^2 = c \n" ); document.write( "sin^2*(a-b) + b = c \n" ); document.write( "sin^2 = (c-b)/(a-b) \n" ); document.write( "====================== \n" ); document.write( "tan^2 = sin^2/cos^2 \n" ); document.write( "tan^2 = ((c-b)/(a-b))/((a-c)/(a-b)) \n" ); document.write( "tan^2 = (c-b)/(a-c) \n" ); document.write( "tan = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |