document.write( "Question 95751This question is from textbook
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document.write( ": Carol has 18 coins with a total value of $3.45. If the coins are dimes and quaters, how many of each kind are there? \n" );
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Algebra.Com's Answer #69773 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Let D represent the number of dimes and Q represent the number of quarters. \n" ); document.write( ". \n" ); document.write( "Since you are told that the number of coins is 18, you can add the number of dimes (D) to \n" ); document.write( "the number of quarters (Q) and set that sum equal to 18. In equation form this is: \n" ); document.write( ". \n" ); document.write( "D + Q = 18 <=== call this \"equation 1\" \n" ); document.write( ". \n" ); document.write( "The total amount of the coins is $3.45 or 345 cents. Each dime is 10 cents and each quarter \n" ); document.write( "is 25 cents. Therefore, if you multiply the number of dimes (D) times 10 (the number of \n" ); document.write( "cents per dime), you will get the total number of cents for all the dimes. Similarly, if \n" ); document.write( "you multiply the number of quarters (Q) times 25 (the number of cents per quarter), you \n" ); document.write( "will get the total number of cents for all the quarters. And when you add the total \n" ); document.write( "cents for dimes to the total cents for quarters, the sum is to be 345 cents. In equation \n" ); document.write( "form this is: \n" ); document.write( ". \n" ); document.write( "10D + 25Q = 345 <=== call this \"equation 2\" \n" ); document.write( ". \n" ); document.write( "Now you can return to equation 1 and solve it for either D or Q. Suppose you solve it \n" ); document.write( "for D by subtracting Q from each side of the equation. When you do that you get: \n" ); document.write( ". \n" ); document.write( "D = 18 - Q \n" ); document.write( ". \n" ); document.write( "Now return to equation 2 and since D is equal to 18 - Q you can substitute 18 - Q for D \n" ); document.write( "in equation 2. When you do that equation 2 becomes: \n" ); document.write( ". \n" ); document.write( "10(18 - Q) + 25Q = 345 \n" ); document.write( ". \n" ); document.write( "Do the multiplication of each of the two terms in parentheses by the 10 and the equation becomes: \n" ); document.write( ". \n" ); document.write( "180 - 10Q + 25Q = 345 \n" ); document.write( ". \n" ); document.write( "Get rid of the 180 on the left side by subtracting 180 from both sides. When you do that \n" ); document.write( "the equation is reduced to: \n" ); document.write( ". \n" ); document.write( "-10Q + 25Q = 165 \n" ); document.write( ". \n" ); document.write( "On the left side combine the -10Q and the +25Q to get +15Q: \n" ); document.write( ". \n" ); document.write( "15Q = 165 \n" ); document.write( ". \n" ); document.write( "Finally, solve for Q by dividing both sides by 15 to get: \n" ); document.write( ". \n" ); document.write( "Q = 165/15 = 11 \n" ); document.write( ". \n" ); document.write( "This says that you have 11 quarters and since you know there are 18 coins, the remaining \n" ); document.write( "7 coins must be the number of dimes. \n" ); document.write( ". \n" ); document.write( "Check by determining that 11 quarters at 25 cents per quarter is $2.75 and then determining \n" ); document.write( "that 7 dimes is $0.70. The total of $2.75 and $0.70 is $3.45 just as the problem said it was. \n" ); document.write( ". \n" ); document.write( "Therefore, the answer to this problem is 11 quarters and 7 dimes. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem and a way to go about solving it. \n" ); document.write( ". \n" ); document.write( " |