document.write( "Question 1083682: Hello, I have two Similar cones Large and small. Large cone is 9cm radius 15 cm slant height. The small cone has a lateral area of 60 pi.
\n" ); document.write( "How do I find the volume of the small cone?
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Algebra.Com's Answer #697718 by addingup(3677)\"\" \"About 
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radius: r
\n" ); document.write( "length of the slant side: l
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\n" ); document.write( "height: h = sqrt(l^2-r^2)
\n" ); document.write( "your large cone:
\n" ); document.write( "h = sqrt(15^2-9^2) = 12
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\n" ); document.write( "Area of the base : Pi*r^2
\n" ); document.write( "Lateral area . . : Pi*r*l (large cone: Pi*9*15 = Pi*135 = 424.12)
\n" ); document.write( "Area of the cone: Pi*r^2+Pi*r*l
\n" ); document.write( "your large cone:
\n" ); document.write( "area = (Pi*9^2)+(Pi*9*15) = 254.47+424.12 = 678.58 is the total area of the large cone
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\n" ); document.write( "Volume of the cone: (Pi*r^2*h)/3 = (Pi*81*12)/3 = 1,017.88
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\n" ); document.write( "Your small cone has a lateral area of 60*Pi = 188.50 and from the formula we know that 60 = r*l. But here I get stuck. How are your cones similar? Do they have the same lateral area ratio, 424.12:188.50?
\n" ); document.write( "I somehow don't think so, I think it's something else. Do they have the same slant height? Or the same height? or the same radius?
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