document.write( "Question 1083682: Hello, I have two Similar cones Large and small. Large cone is 9cm radius 15 cm slant height. The small cone has a lateral area of 60 pi.
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Algebra.Com's Answer #697710 by MathLover1(20850)\"\" \"About 
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\r
\n" ); document.write( "\n" ); document.write( " Large cone is\"+r%5B1%5D=9cm\" and \"L%5B1%5D=15cm+\" slant height\r
\n" ); document.write( "\n" ); document.write( "small cone has a lateral area of \"LA=60+pi\"\r
\n" ); document.write( "\n" ); document.write( "The lateral area of a cone is\r
\n" ); document.write( "\n" ); document.write( " \"LA=pi+%2A+r+%2A+L\" where \"r\" is the radius and \"L\" is the slant height\r
\n" ); document.write( "\n" ); document.write( "\"60pi=pi+%2A+r+%2A+L\"\r
\n" ); document.write( "\n" ); document.write( "\"60=+r+%2A+L\"\r
\n" ); document.write( "\n" ); document.write( "\"60%2FL=+r+\"\r
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\n" ); document.write( "\n" ); document.write( "since cones similar, radii and slant heights are proportional:\r
\n" ); document.write( "\n" ); document.write( "\"r%5B1%5D%2Fr=L%5B1%5D%2FL\"\r
\n" ); document.write( "\n" ); document.write( "\"9%2F%2860%2FL%29=15%2FL\"\r
\n" ); document.write( "\n" ); document.write( "\"9L%2F60=15%2FL\"\r
\n" ); document.write( "\n" ); document.write( "\"3L%2F20=15%2FL\"\r
\n" ); document.write( "\n" ); document.write( "\"3L%2AL=15%2A20\"\r
\n" ); document.write( "\n" ); document.write( "\"L%5E2=%2815%2A20%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"L%5E2=5%2A20\"\r
\n" ); document.write( "\n" ); document.write( "\"L%5E2=100\"\r
\n" ); document.write( "\n" ); document.write( "\"L=10cm\"-> slant height of a small cone\r
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\n" ); document.write( "\n" ); document.write( "\"60%2FL=+r+\"\r
\n" ); document.write( "\n" ); document.write( "\"60%2F10cm=+r+\"\r
\n" ); document.write( "\n" ); document.write( "\"6cm=+r+\"-> radius of a small cone\r
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\n" ); document.write( "\n" ); document.write( "now we can find a volume:\r
\n" ); document.write( "\n" ); document.write( "\"V=%281%2F3%29b%2Ah\" where \"b\" is base and \"h\" height of the cone\r
\n" ); document.write( "\n" ); document.write( "base is a circle: area is \"r%5E2pi\"\r
\n" ); document.write( "\n" ); document.write( "so, \"V=%281%2F3%29r%5E2%2Api%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "we will find height using Pythagorean theorem: \r
\n" ); document.write( "\n" ); document.write( "\"h%5E2=L%5E2-r%5E2\" ->\"h=sqrt%2810%5E2-6%5E2%29\" ->\"h=sqrt%28100-36%29\"->\"h=sqrt%2864%29\"->\"h=8cm\"\r
\n" ); document.write( "\n" ); document.write( "\"V=%281%2F3%29%286cm%29%5E2%2Api%2A8cm\"\r
\n" ); document.write( "\n" ); document.write( "\"V=%281%2Fcross%283%29%29%28cross%2836%2912cm%5E2%2Api%2A8cm%29\"\r
\n" ); document.write( "\n" ); document.write( "\"V=12cm%5E2%2Api%2A8cm\"\r
\n" ); document.write( "\n" ); document.write( "\"V=96cm%5E3%2Api\"\r
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