document.write( "Question 1083349: find the acute angle between the following straight lines \r
\n" ); document.write( "\n" ); document.write( "y=(0.5)(x)+1 and y=-(1/3)(x)+2
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Algebra.Com's Answer #697591 by Theo(13342)\"\" \"About 
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the angle is 45 degrees as best i can see.\r
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\n" ); document.write( "\n" ); document.write( "i believe you can just go by the slope.\r
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\n" ); document.write( "\n" ); document.write( "the y-intercept determines where the intersection of the 2 lines will be but it doesn't change the angle between the lines.\r
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\n" ); document.write( "\n" ); document.write( "i tested this out and it appears to be correct.\r
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\n" ); document.write( "\n" ); document.write( "a slope of .5 means the opposite side of the right triangle formed is 1/2 the length of the adjacent side.\r
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\n" ); document.write( "\n" ); document.write( "if the adjacent side is equal to 1, then the opposite side is equal to 1/2 and the tangent of the angle is equal to 1/2 / 1 which is equal to 1/2 which gives you an angle of 26.56505118 when you find the arc tangent of 1/2.\r
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\n" ); document.write( "\n" ); document.write( "a slope of -1/3 means the opposite side is 1/3 the length of the adjacent side.\r
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\n" ); document.write( "\n" ); document.write( "if the adjacent side is equal to 1, then the opposite side is equal to -1/3 and the tangent of the angle is equal to -1/3 / 1 which gives you an angle of -18.43494882 degrees.\r
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\n" ); document.write( "\n" ); document.write( "add these angles together and you get an angle of 45 degrees between the two lines.\r
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\n" ); document.write( "\n" ); document.write( "these are vertical angles of the intersection.\r
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\n" ); document.write( "\n" ); document.write( "the other vertical angles of the intersection will be 180 - 45 = 135 degrees.\r
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\n" ); document.write( "\n" ); document.write( "45 degrees are the acute vertical angles.\r
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\n" ); document.write( "\n" ); document.write( "135 degrees are the obtuse vertical angles.\r
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\n" ); document.write( "\n" ); document.write( "the graph of these two lines looks like this.\r
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