document.write( "Question 95731: The perimeter of a rectangle is 154 inches. The length exceeds the width by 39 inches. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #69754 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=W+39 \n" ); document.write( "2L+2W=154 \n" ); document.write( "2(W+39)+2W=154 \n" ); document.write( "2W+78+2W=154 \n" ); document.write( "4W=154-78 \n" ); document.write( "4W=76 \n" ); document.write( "W=76/4 \n" ); document.write( "W=19 FOR THE WIDTH \n" ); document.write( "L=19+39=58 FOR THE LENGTH \n" ); document.write( "PROOF \n" ); document.write( "2*58+2*19 \n" ); document.write( "116+38=154 \n" ); document.write( "154=154 \n" ); document.write( " |