document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083508>Question 1083508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation\r<BR>\n" );
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document.write( "17/m+1/3=2/5m+29/6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697503 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697503\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 17/m + 1/3=2/5m + 29/6 <BR>\n" );
document.write( "Multiply everything by 30m<BR>\n" );
document.write( "510 + 10m=12+145 m<BR>\n" );
document.write( "498=135m<BR>\n" );
document.write( "m=3.69<BR>\n" );
document.write( "Note my interpretation of 2/5m, which is different from (2/5)m<BR>\n" );
document.write( "Check using 3.7<BR>\n" );
document.write( "17/3.7+1/3=2/18.5+29/6<BR>\n" );
document.write( "4.6+0.33=0.11+4.83<BR>\n" );
document.write( "This is 4.93=4.94, and that is very close given that I used 3.7 and not 3.688 </SPAN>\n" );
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