document.write( "Question 1083384: The number of grams of a certain radioactive substance present at time t is given by the formula A=200e^-0.005t, where t is the number of years. Find the number of grams that are present at time t=0 and at time t=800 \n" ); document.write( "
Algebra.Com's Answer #697449 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
You have your formula: \"A=200%2Ae%5E%28-0.005t%29\"
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\n" ); document.write( "You are given the independent variable values to use:
\n" ); document.write( " \"system%28t=0%2Cor%2Ct=800%29\"\r
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\n" ); document.write( "Make the substitutions and evaluate the result for each:\r
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\n" ); document.write( "\n" ); document.write( " \"200%2Ae%5E%28-0.005%2A0%29=200%2Ae%5E0=200%2A1=200\",
\n" ); document.write( "which is not complicated... \r
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\n" ); document.write( "\n" ); document.write( "AND for the other, use a hand-held calculator for \"200%2Ae%5E%28-0.005%2A800%29=200%2Ae%5E%28-4%29\"
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