document.write( "Question 95717: Sorry. Last one was screwed up.\r
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document.write( "sinx/sinx+cosx = tanx/1+tanx \n" );
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Algebra.Com's Answer #69744 by bucky(2189) ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Use the identity: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and on the right side substitute \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The denominator contains 1. Replace 1 with an equivalent \n" ); document.write( "become: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Notice now that the two terms in the denominator both have the common denominator \n" ); document.write( "of \n" ); document.write( "that common denominator to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Note that on the right side you are dividing by the fraction \n" ); document.write( "To divide by a fraction you can invert the fraction and multiply. This converts the problem \n" ); document.write( "to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "On the right side cancel the \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Notice that with this set of cancellations the right side now equals the left side of \n" ); document.write( "the equation. Therefore, the original problem has been proven. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand trig a little better. \n" ); document.write( ". \n" ); document.write( " |