document.write( "Question 1083425: I am not sure if I am posting this in the right place \r
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document.write( "A contractor mixes concrete from bags of pre-mix. How many bags with 10 % cement should he mix with 4 bags of 12.5% cement to produce a mix containing 11% cement?
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document.write( "A. 10 Bags
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document.write( "B. 8 Bags
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document.write( "C. 6 Bags
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document.write( "D. 15 bg
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Algebra.Com's Answer #697414 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let x = number of 10% bags of cement needed \n" ); document.write( "The goal is to find the number that replaces x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's say that each bag weighs 100 pounds.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A single 10% cement bag has 10 pounds of pure cement (0.1*100 = 10) \n" ); document.write( "x of these bags would have 10x pounds of pure cement \n" ); document.write( "In total, we have 100*x = 100x pounds of material (cement+other stuff)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A single 12.5% bag has 12.5 pounds of pure cement (0.125*100 = 12.5) \n" ); document.write( "Four of these bags would have 4*12.5 = 50 pounds of pure cement \n" ); document.write( "In total, we have 4*100 = 400 pounds of material (cement+other stuff)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Mixing the x 10% bags and the four 12.5% bags yields \n" ); document.write( "10x+50 pounds \n" ); document.write( "of pure cement\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This would be out of 100x+400 pounds total (of cement plus other material)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide the two expressions (10x+50 and 100x+400) and set this ratio equal to the desired percentage we want, which is 11% = 0.11, so \n" ); document.write( "(amount of pure cement)/(amount total) = percentage desired \n" ); document.write( "(10x+50)/(100x+400) = 0.11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for x \n" ); document.write( "(10x+50)/(100x+400) = 0.11 \n" ); document.write( "[(10x+50)/(100x+400)]*(100x+400) = 0.11*(100x+400) \n" ); document.write( "10x+50 = 0.11*(100x)+0.11*(400) \n" ); document.write( "10x+50 = 11x+44 \n" ); document.write( "10x+50-44 = 11x+44-44 \n" ); document.write( "10x+6 = 11x \n" ); document.write( "10x+6-10x = 11x-10x \n" ); document.write( "6 = x \n" ); document.write( "x = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------------------- \n" ); document.write( "--------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We need 6 bags of the 10% mix. \n" ); document.write( " |