document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083425>Question 1083425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am not sure if I am posting this in the right place \r<BR>\n" );
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document.write( "A contractor mixes concrete from bags of&#8203; pre-mix. How many bags with 10 % cement should he mix with 4 bags of 12.5% cement to produce a mix containing 11% &#8203;cement?<BR>\n" );
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document.write( "A. 10 Bags<BR>\n" );
document.write( "B. 8 Bags<BR>\n" );
document.write( "C. 6 Bags<BR>\n" );
document.write( "D. 15 bg<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697413 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=bags of 10%<BR>\n" );
document.write( ".10x+4*.125=(x+4)(.11)<BR>\n" );
document.write( ".10x+.5=.11x+.44<BR>\n" );
document.write( ".01x=.06<BR>\n" );
document.write( "x=6 bags<BR>\n" );
document.write( "C.<BR>\n" );
document.write( "check 6 * 10 +4*12.5=110=10*11 </SPAN>\n" );
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