document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083268>Question 1083268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A recent quality control test at a local chocolate bar factory finds that the mass of the chocolate bars appear to be normally distributed with a mean mass of 52g and a standard deviation of 1.02g. What percentage of chocolate bars are between 49.96g and 53.02g? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697411 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "=(49.96-52)/1.02=-2<BR>\n" );
document.write( "z=(53.02-52)/1.02=+1<BR>\n" );
document.write( "probability of z between -2 and +1=0.8186 or 81.86% </SPAN>\n" );
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