document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083402>Question 1083402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The function f(x)= 1/2x-6 was replaced with f(x+k)=1/2x-4. What is the<BR>\n" );
document.write( "value of k?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697389 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/(2x-6), I am assuming the parentheses belong<BR>\n" );
document.write( "When k is added to x,  it is 1/(2(x+k)-6)=1/(2x+2k-6)<BR>\n" );
document.write( "this equals 1/(2x-4)<BR>\n" );
document.write( "therefore, 2x+2k-6=2x-4<BR>\n" );
document.write( "2k=2, k=1, ANSWER\r<BR>\n" );
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document.write( "====================<BR>\n" );
document.write( "(1/2)x-6 with (x+k)=(1/2)(x+k)=(1/2)(x)-4<BR>\n" );
document.write( "(1/2)x-(1/2)k=(1/2)x-4<BR>\n" );
document.write( "k=4 ANSWER<BR>\n" );
document.write( "(1/2)(x+4)-6=(1/2)x+2-6=(1/2)x-4\r<BR>\n" );
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