document.write( "Question 1083388: the probability of an employee getting a raise is 0.15. the probability of an employee getting a promotion is 0.23. the probability of an employee getting a raise and a promotion is 0.08. what is the probability of a randomly selected employee getting a raise or a promotion \n" ); document.write( "
Algebra.Com's Answer #697388 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
P(OR)=P(A)+P(B)-P(A and B), the last being double counting is removed.
\n" ); document.write( "=0.15+0.23-0.08=0.30
\n" ); document.write( "
\n" );