document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083377>Question 1083377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eexpand the (1+2x)7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697364 by </B><A HREF=/tutors/aboutme.mpl?userid=natolino_2017><B>natolino_2017(77)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=natolino_2017><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697364\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the rule of Newton Binomial:\r<BR>\n" );
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document.write( "(1+2x)^7 = sum((7Ck)(1)^(7-k)(2x)^k from k= 0 to k = 7.\r<BR>\n" );
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document.write( "Se the (1)^k = 1 for any value ok k.\r<BR>\n" );
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document.write( "= 7C0 + 7C1(2x) + 7C2(4x^2) + 7C3(8x^3) + 7C4(16x^4) + 7C5(32x^5) + 7C6(64x^6) +7C7(128x^7)\r<BR>\n" );
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document.write( "= 1 + 14x + 84x^2 + 280x^3 + 560x^4 + 672x^5 + 448x^6 + 128x^7.\r<BR>\n" );
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document.write( "Remember that nCk = n!/((n-k)!(k!)) is n>=k and n and k are natural numbers  or zero.\r<BR>\n" );
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document.write( "@natolino_ </SPAN>\n" );
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