document.write( "Question 1083333: Why x = 7 is not a solution to the equation:\r
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Algebra.Com's Answer #697339 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
log((x+3)/(x-8)) would lead to the log of a negative number which is not allowed.\r
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\n" ); document.write( "\n" ); document.write( "i believe the equation is log((x+3)*(x-8)) + log((x+3)/(x-8)) = 2\r
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\n" ); document.write( "\n" ); document.write( "that makes more sense than having the (x-8) outside of the log function as you show it.\r
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\n" ); document.write( "\n" ); document.write( "i graphed it and found x to be equal to -13.\r
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\n" ); document.write( "\n" ); document.write( "that value of x makes the equation true.\r
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\n" ); document.write( "\n" ); document.write( "i then proceeded to solve it algebraically and came up with the source of the problem.\r
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\n" ); document.write( "\n" ); document.write( "here's what i did:\r
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\n" ); document.write( "\n" ); document.write( "start with log((x+3)*(x-8)) + log((x+3)/(x-8)) = 2\r
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\n" ); document.write( "\n" ); document.write( "this is equivalent to log(x+3) + log(x-8) + log(x+3) - log(x-8) = 2\r
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\n" ); document.write( "\n" ); document.write( "the plus and minus log(x-8) cancel out and you are left with:\r
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\n" ); document.write( "\n" ); document.write( "log(x+3) + log(x+3) = 2\r
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\n" ); document.write( "\n" ); document.write( "this is equivalent to 2 * log(x+3) = 2\r
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\n" ); document.write( "\n" ); document.write( "i then divided both sides of the equation by 2 to get log(x+3) = 1\r
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\n" ); document.write( "\n" ); document.write( "this is true if and only if 10^1 = x+3 which results in x = 7.\r
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\n" ); document.write( "\n" ); document.write( "that doesn't work because log((x+3)/(x-8)) becomes the log of a negative number which is not allowed.\r
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\n" ); document.write( "\n" ); document.write( "i then looked at it in a different way.\r
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\n" ); document.write( "\n" ); document.write( "starting from 2 * log(x+3)) = 2, i used the fact that 2 * log(x+3)) is equivalent to log((x+3)^2), so the equation became:\r
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\n" ); document.write( "\n" ); document.write( "log((x+3)^2) = 2\r
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\n" ); document.write( "\n" ); document.write( "this is true if and only if 10^2 = (x+3)^2\r
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\n" ); document.write( "\n" ); document.write( "this becomes 100 = (x+3)^2\r
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\n" ); document.write( "\n" ); document.write( "take the square root of both sides of the equation and you get:\r
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\n" ); document.write( "\n" ); document.write( "(x+3) = plus or minus 10.\r
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\n" ); document.write( "\n" ); document.write( "x + 3 = 10 leads to x = 7\r
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\n" ); document.write( "\n" ); document.write( "x + 3 = -10 leads to x = -13\r
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\n" ); document.write( "\n" ); document.write( "bingo !!!!!\r
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\n" ); document.write( "\n" ); document.write( "x = -13 is the answer.\r
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\n" ); document.write( "\n" ); document.write( "this was confirmed graphically as shown below:\r
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