document.write( "Question 1083298: if sin(x)+cos(x)=1/2 then find the values :\r
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Algebra.Com's Answer #697325 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
(1) sin(x)*cos(x)
Given: \"sin%28x%29%2Bcos%28x%29=1%2F2\"\r\n" );
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document.write( "Square both sides:\r\n" );
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document.write( "\"sin%5E2%28x%29%2B+2sin%28x%29cos%28x%29%2B+cos%5E2%28x%29=1%2F4\"\r\n" );
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document.write( "\"sin%5E2%28x%29%2B+cos%5E2%28x%29+%2B+2sin%28x%29cos%28x%29=1%2F4\"\r\n" );
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document.write( "\"%28sin%5E2%28x%29%2B+cos%5E2%28x%29%5E%22%22%29+%2B+2sin%28x%29cos%28x%29=1%2F4\"\r\n" );
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document.write( "\"1%2B2sin%28x%29cos%28x%29=1%2F4\"\r\n" );
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document.write( "\"2sin%28x%29cos%28x%29=-3%2F4\"\r\n" );
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document.write( "\"sin%28x%29cos%28x%29=-3%2F8\"\r\n" );
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(2) sin^2(x)+cos^2(x)
That's just 1.\r\n" );
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(3) sin^3(x)+cos^3(x)
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document.write( "Factor as the sum of two cubes:\r\n" );
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document.write( "Plug in the values from above parts:\r\n" );
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document.write( "\"%281%2F2%29%281-%28-3%2F8%29%5E%22%22%29\"\r\n" );
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document.write( "\"%281%2F2%29%281%2B3%2F8%29\"\r\n" );
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document.write( "\"%281%2F2%29%2811%2F8%29\"\r\n" );
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document.write( "\"11%2F16\"\r\n" );
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document.write( "Edwin
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