document.write( "Question 1083313: Please Help! I am new to this page I have been working on this question for a while and I can not figure it out. \r
\n" ); document.write( "\n" ); document.write( "In 1993, the life expectancy of males in a certain country was 73.6 years. In 1998​, it was 77.2 years. Let E represent the life expectancy in year t and let t represent the number of years since 1993\r
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Algebra.Com's Answer #697322 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "In \"1993\", the \"life expectancy of males in a certain country\" was \"73.6\" years.
\n" ); document.write( "so, \"E=73.6\" years and \"t=1993\"\r
\n" ); document.write( "\n" ); document.write( " In \"1998\"​, it was \"77.2\" years, so \r
\n" ); document.write( "\n" ); document.write( "\"E=77.2\" years and \"t=1998\"\r
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\n" ); document.write( "\n" ); document.write( "The linear function \"E%28t%29\" that fits the data is:\r
\n" ); document.write( "\n" ); document.write( "\"E%28t%29=at+%2B+b\"................use \"E=73.6\" years and \"t=1993\"\r
\n" ); document.write( "\n" ); document.write( "\"73.6=a%2A1993+%2B+b\"....solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=73.6-a%2A1993\".........eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"E%28t%29=at+%2B+b\"................use \"E=77.2\" years and \"t=1998\"\r
\n" ); document.write( "\n" ); document.write( "\"77.2=a%2A1998+%2B+b\"....solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=77.2-a%2A1998\".........eq.2\r
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\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have\r
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\n" ); document.write( "\n" ); document.write( "\"73.6-a%2A1993=+77.2-a%2A1998\"\r
\n" ); document.write( "\n" ); document.write( "\"73.6-77.2=a%2A1993-a%2A1998\"\r
\n" ); document.write( "\n" ); document.write( "\"-3.6=a%281993-1998%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-3.6=a%28-5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=-3.6%2F%28-5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=+0.72\"\r
\n" ); document.write( "\n" ); document.write( "now find \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=73.6-a%2A1993\".........eq.1\r
\n" ); document.write( "\n" ); document.write( "\"b=73.6-0.72%2A1993\"\r
\n" ); document.write( "\n" ); document.write( "\"b=73.6-1434.96\"\r
\n" ); document.write( "\n" ); document.write( "\"b=-1361.36\"\r
\n" ); document.write( "\n" ); document.write( "then, equation is:\r
\n" ); document.write( "\n" ); document.write( "\"E%28t%29=at+%2B+b\"...if \"a=+0.72\" and \"b=-1361.36\"\r
\n" ); document.write( "\n" ); document.write( "\"E%28t%29=0.72t+-1361.36\"\r
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