document.write( "Question 95706This question is from textbook
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document.write( ": A landscaper, who just completed a rectangular flower garden measuring 6 feet by 10 feet, orders 1 cubic yard of premixed cement, all of which is to be used to create a border of uniform width around the garden. If the border is to have a depth of 3 inches, how wide will the border be?\r
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document.write( "Thanks so much for your help! I'm pulling my hair out.\r
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document.write( "Connie \n" );
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Algebra.Com's Answer #69730 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! START BY DRAWING A SKETCH OF THE 6 BY 10 PLOT. NOW DRAW A SMALL BORDER AROUND IT & LABEL THE WIDTH X. \n" ); document.write( "THE AREA TO BE FILLED IN IS: \n" ); document.write( "(6+2X)+(10+2X)-6*10 \n" ); document.write( "60+20X+12X+4X^2-60 \n" ); document.write( "4X^2+32X IS THE AREA TO BE CEMENTED TO A DEPTH OF 3 INCHES WHICH IS 3/12 FEET OR .25 FEET. \n" ); document.write( "THE AMOUNT OF CEMENT IN FEET IS 38383=27 CUBIC FEET. \n" ); document.write( "NEW WE SOLVE FOR THE VALUE OF X: \n" ); document.write( "(4X^2+32X)*.25=27 \n" ); document.write( "X^2+8X-27=0 \n" ); document.write( "USING THE QUADRATIC EQUATION WE GET: \n" ); document.write( " \n" ); document.write( "X=(-8+-SQRT[8^8-4*1*-27])/281 \n" ); document.write( "X=(-8=-SQRT(64*108])/2 \n" ); document.write( "X=(-8+-SQRT172)/2 \n" ); document.write( "X=(-8+-13.11)/2 \n" ); document.write( "X=(-8+13.11)/2 \n" ); document.write( "X=5.11/2 \n" ); document.write( "X=2.56 FEET IS THE WIDTH OF THE BORDER NEEDED FOR THE 27 CUBIC FEET OF CEMENT. \n" ); document.write( "FILL IN THESE MEASUREMENTS IN YOUR DIAGRAM AND VERIFY THE ANSWERS OR 2.56 FEET FOR THE WIDTH & .25 FEET FOR THE DEPTH. \n" ); document.write( " \n" ); document.write( " |