document.write( "Question 1083271: GEmployees have a choice of going out to lunch or eating in the cafeteria. There is a 40% chance that an employee eats lunch in the cafeteria. The probability that a worker arrives back from lunch on time is .44. The probability that an employee arrives back from lunch on time given that he/she ate in the cafeteria is .6. \r
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document.write( "What is the probability an employee eats in the cafeteria and arrives late from lunch?
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document.write( "What is the probability an employee does not eat in the cafeteria and does not arrive late from lunch?
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document.write( "What is the probability an employee does not eat in the cafeteria given that he/she arrives on time?
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document.write( "What is the probability an employee eats in the cafeteria or arrives late from lunch?
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document.write( "What is the probability an employee does not eat in the cafeteria given that he/she does not arrive on time? \n" );
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Algebra.Com's Answer #697279 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Tree diagram \n" ); document.write( ".4C=======================.6 NO \n" ); document.write( ".6 on time (0.24)======= \n" ); document.write( ".4 late (0.16)========== \n" ); document.write( "This is how I understand the problem. Then there is an overall probability that a worker arrives back on time is 0.44, which means a 0.20 probability that the worker who eats out arrives on time. That means that they have a 1/3 probability of returning on time and a 2/3 probability of being late.\r \n" ); document.write( "\n" ); document.write( "With these assumptions. \n" ); document.write( "a. Eats in cafeteria and arrives late is 0.16, 0.4*0.4 \n" ); document.write( "b. Does not eat there and is not late 0.20 \n" ); document.write( "c. Given that they arrive on time (44%) probability they didn't eat in cafeteria is 20/44=0.45 \n" ); document.write( "d. Eats in cafeteria=0.4+arrives late 0.56- both -0.16=0.80 \n" ); document.write( "e. Given that did not arrive on time (0.56) probability they did not eat in the cafeteria (.40) so that is 0.71. \n" ); document.write( " |