document.write( "Question 1083191: A large cone of given size is being drained of water at the constant rate of 15 cubic cm each second. The water's surface level in the cone falls as a result. At what rate is the water level falling when the water is 4cm deep? \n" ); document.write( "
Algebra.Com's Answer #697212 by Alan3354(69443)\"\" \"About 
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A large cone of given size is being drained of water at the constant rate of 15 cubic cm each second. The water's surface level in the cone falls as a result. At what rate is the water level falling when the water is 4cm deep?
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\n" ); document.write( "No dimensions given.
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\n" ); document.write( "\"V+=+pi%2Ar%5E2%2Ah%2F3\"
\n" ); document.write( "r = h/k where k is a constant = height/radius of the cone.
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\n" ); document.write( "\"V+=+pi%2Ak%5E2%2Ah%5E3%2F3\"
\n" ); document.write( "\"dV%2Fdt+=+pi%2Ak%5E2%2Ah%5E2%2A%28dh%2Fdt%29\"
\n" ); document.write( "\"15+=+pi%2Ak%5E2%2A16%2A%28dh%2Fdt%29\"
\n" ); document.write( "\"dh%2Fdt+=+15%2F%2816pi%2Ak%5E2%29\"\r
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