document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95703>Question 95703</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977274/algebrahomeworkh>Geometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> #32) The lengths of the sides of three squares are s, s+1, s+2. If their total area is 365cm^2, find their total perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69721 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69721\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S^2+(S+1)^2+(S+2)^2=365<BR>\n" );
document.write( "S^2+S^2+2S+1+S^2+4S+4=365<BR>\n" );
document.write( "3S^2+6S+5-365=0<BR>\n" );
document.write( "3S^2+6S-360=0<BR>\n" );
document.write( "3(S^2+2S-120=0<BR>\n" );
document.write( "(S-10)(S+12)=0<BR>\n" );
document.write( "S-10=0<BR>\n" );
document.write( "S=10 FOR THE SIDE OF THE SMALLER SQUARE<BR>\n" );
document.write( "S=11 & S=12 FOR THE OTHER 2 SQUARES<BR>\n" );
document.write( "PERIMETERS=4*10+4*11+4*12=40+44+48=132CM.   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );