document.write( "Question 1083079: Mean score of an statistic exam is 75 and normally distributed. The probability between 55 and 60 is 4.41% and the probability of students scoring more, 90 is 6.61%.
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Algebra.Com's Answer #697175 by mathmate(429)\"\" \"About 
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For this particular problem, it can be solved quickly, as follows:
\n" ); document.write( "\"P%2860%3CX%3C95+%29\"
\n" ); document.write( "=\"P%28X%3C95%29-P%28X%3C60%29\"
\n" ); document.write( "=\"P%28X%3E55%29-P%28X%3E90%29\" ..... recall that mean=75, and normal distr. is symm about mean
\n" ); document.write( "=\"P%2855%3CX%3C60%29%2BP%28X%3E60%29-0.0661\"
\n" ); document.write( "=\"0.0441%2B%281-P%28X%3E90%29%29-0.0661\"
\n" ); document.write( "=\"0.0441%2B%281-0.0661%29-0.0661\"
\n" ); document.write( "=\"0.9119\"\r
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\n" ); document.write( "\n" ); document.write( "A more general way is to solve for the standard deviation, and solve accordingly. Standard deviation will be found to be 9.9639.
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