document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083078>Question 1083078</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Measurements were taken of the weight (to the nearest 5 Kg’s) of 100 individuals from a certain population. The results are shown in the table below.\r<BR>\n" );
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document.write( "  Weight (Kg)                                                Number of Individuals<BR>\n" );
document.write( " 50                                                                      1 <BR>\n" );
document.write( "55                                                                       8 <BR>\n" );
document.write( "60                                                                      19 <BR>\n" );
document.write( "65                                                                      38 <BR>\n" );
document.write( "70                                                                      22 <BR>\n" );
document.write( "75                                                                      10 <BR>\n" );
document.write( "80                                                                       2\r<BR>\n" );
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document.write( "(i) Find the mean, median and mode of this data set.<BR>\n" );
document.write( " (ii) Find the standard deviation and variance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697155 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 50 1 =50<BR>\n" );
document.write( "55 8 =440<BR>\n" );
document.write( "60 19 =1140<BR>\n" );
document.write( "65 38 =2470<BR>\n" );
document.write( "70 22 =1540<BR>\n" );
document.write( "75 10 =750<BR>\n" );
document.write( "80 2=160<BR>\n" );
document.write( "sum is 6550<BR>\n" );
document.write( "mean is that divided by 100 or 65.5 kg<BR>\n" );
document.write( "median is between 50th and 51st, which is 65 kg<BR>\n" );
document.write( "mode is most common or 65 kg<BR>\n" );
document.write( "variance is (-15)^2*1=225<BR>\n" );
document.write( "+(-10^2)*8=800<BR>\n" );
document.write( "25*19=475<BR>\n" );
document.write( "+0<BR>\n" );
document.write( "+550<BR>\n" );
document.write( "1000<BR>\n" );
document.write( "+450<BR>\n" );
document.write( "Adds to 3500<BR>\n" );
document.write( "if population, divide by 100 and variance is 35 and sd is its sqrt, or 5.92 kg<BR>\n" );
document.write( "If sample, divide by 99 and variance is 35.35 and sd is 5.95 kg.<BR>\n" );
document.write( "I am not taking the middle of 50 and 55, because these are to the nearest 5 kg, which makes each group centered on a kg evenly divisible by 5.<BR>\n" );
document.write( " </SPAN>\n" );
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