document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083141>Question 1083141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Graph 6x-5y=30 using a table of value\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697139 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697139\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The easiest way is to set one variable equal to 0 and solve for the other.  This works well when the coefficients are factors of the constant (6 and 5 are factors of 30)<BR>\n" );
document.write( "x---------y<BR>\n" );
document.write( "0======-6<BR>\n" );
document.write( "5---------0<BR>\n" );
document.write( "There are other values one may use, but two points determine a line.<BR>\n" );
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