document.write( "Question 1083063: Board of directors of a company wants to
\n" ); document.write( "randomly form a quality management
\n" ); document.write( "committee of 5 members to monitor quality
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\n" ); document.write( "\n" ); document.write( "The company has 5
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\n" ); document.write( "\n" ); document.write( "What is the probability that the committee
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Algebra.Com's Answer #697061 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
There are 5 scientists
\n" ); document.write( "There are 4 engineers
\n" ); document.write( "There are 6 accountants
\n" ); document.write( "In total there are 5+4+6 = 15 people.\r
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\n" ); document.write( "\n" ); document.write( "Using the combination formula, there are 15 C 5 = 3003 ways to pick 5 people from a pool of 15 candidates. This is where order does not matter. With many committees, the members are equal in standing making order not important. That is the case here. \r
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\n" ); document.write( "\n" ); document.write( "There are 5 C 2 = 10 different ways to pick 2 scientists from a pool of 5
\n" ); document.write( "There are 4 C 1 = 4 different ways to pick 1 engineer from a pool of 4
\n" ); document.write( "There are 6 C 2 = 15 different ways to pick 2 accountants from a pool of 6
\n" ); document.write( "Again order doesn't matter.\r
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\n" ); document.write( "\n" ); document.write( "Multiply those results: 10*4*15 = 600
\n" ); document.write( "So there are 600 ways to pick 2 scientists, 1 engineer and 2 accountants\r
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\n" ); document.write( "\n" ); document.write( "Divide the number of ways to get the outcome we want (600) over the total number of ways to pick a committee (3003) to get 600/3003 = 200/1001 = 0.1998 = 19.98%\r
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\n" ); document.write( "\n" ); document.write( "The decimal and percent values are approximate\r
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\n" ); document.write( "\n" ); document.write( "Final Answer as a fraction: 200/1001
\n" ); document.write( "Final Answer as a decimal: 0.1998 (approximate)
\n" ); document.write( "Final Answer as a percentage: 19.98% (approximate)\r
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\n" ); document.write( "\n" ); document.write( "These are all equivalent ways of stating the same thing. The answer you provide your teacher will depend on the instructions s/he gives you.
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