document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95685>Question 95685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help!<BR>\n" );
document.write( "The question is:<BR>\n" );
document.write( "The Sum of two numbers is 25.  Tweleve less than four times one of the numbers is 16 more than twice the other number.  Find both numbers. \r<BR>\n" );
document.write( "\n" );
document.write( "I tried figuring it out, but I got that 12&39=25, which is not possible.  Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69702 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=25 OR X=25-Y<BR>\n" );
document.write( "4X-12=2Y+16 NOW SUBSTITUTE (25-Y) FOR X IN THE SECOND EQUATION & SOLVE FOR Y:<BR>\n" );
document.write( "4(25-Y)-12=2Y+16<BR>\n" );
document.write( "100-4Y-12=2Y+16<BR>\n" );
document.write( "100-16-12=2Y+4Y<BR>\n" );
document.write( "6Y=72<BR>\n" );
document.write( "Y=72/6<BR>\n" );
document.write( "Y=12 FOR ONE NUMBER.<BR>\n" );
document.write( "X+12=25<BR>\n" );
document.write( "X=25-12<BR>\n" );
document.write( "X=13 FOR THE SECOND NUMBER<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "4*13-12=2*12+16<BR>\n" );
document.write( "52-12=24+16<BR>\n" );
document.write( "40=40  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );