document.write( "Question 1083006: The average speed of an express train is 40 km/h faster than the average speed of a bus. To
\n" ); document.write( "travel 1200km, the bus requires 50% more time than the train. Determine the average
\n" ); document.write( "speeds of the train and the bus \n" ); document.write( "

Algebra.Com's Answer #697014 by josgarithmetic(39620) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "              SPEED       TIME       DISTANCE \r\n" );
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document.write( "TRAIN          r+40       t            1200\r\n" );
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document.write( "BUS            r          t+t/2        1200\r\n" );
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\r
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\n" ); document.write( "\n" ); document.write( " $\"r%283t%2F2%29=1200\"$
\n" ); document.write( " $\"1200%282%2F3%29%281%2Fr%29=t\"$
\n" ); document.write( " $\"t=800%2Fr\"$ \r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( " $\"%28r%2B40%29%28800%2Fr%29=1200\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"%28r%2B40%29%2Fr=12%2F8\"$
\n" ); document.write( " $\"%28r%2B40%29%2Fr=3%2F2\"$
\n" ); document.write( " $\"2%28r%2B40%29=3r\"$
\n" ); document.write( " $\"2r%2B80=3r\"$
\n" ); document.write( " $\"r=80\"$ --- $\"r%2B40=120\"$
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\n" ); document.write( "Bus, 80 km/h
\n" ); document.write( "Train, 120 km/h
\n" ); document.write( "(t=10 hours for the train) \n" ); document.write( "

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