document.write( "Question 1083006: The average speed of an express train is 40 km/h faster than the average speed of a bus. To
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Algebra.Com's Answer #697013 by ikleyn(52798) $\"\"$ $\"About$

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document.write( "Let B be average speed of the bus, in kilometers per hour.\r\n" );
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document.write( "Then the average speed of the train is (B+40) km/h, according to the condition.\r\n" );
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document.write( "The bus covers 1200 km in  hours.\r\n" );
document.write( "The train covers 1200 km in  hours.\r\n" );
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document.write( "The condition says that to travel 1200 km, the bus requires 50% more time than the train. It means that\r\n" );
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document.write( "It is your equation to find the unknown B.\r\n" );
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document.write( "Simplify it step by step, first canceling 1200 in both sides:\r\n" );
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document.write( " =   ---->\r\n" );
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document.write( "B + 40 = 1.5*B  (after cross multiplying)  ---->\r\n" );
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document.write( "0.5B = 40  ---->  B =  = 80 km/h.\r\n" );
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document.write( "Thus the bus speed is 80 km/h.\r\n" );
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document.write( "Then the train speed is (B+40) = 80 + 40 = 120 km/h.\r\n" );
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document.write( "Check.  Bus' time = {{1200/80}}} = 15 hours.\r\n" );
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document.write( "        Train's time =  = 10 hours.\r\n" );
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document.write( "Answer.  The bus' speed = 80 km/h.  The train' speed = 120 km/h.\r\n" );
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