document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1083000>Question 1083000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that P(A)= 0.54, P(B)= 0.71 and P(A and B)= 0.3751.\r<BR>\n" );
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document.write( "A) are A and B disjoint events?\r<BR>\n" );
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document.write( "B) are A and B dependent events?\r<BR>\n" );
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document.write( "C) explain why for parts A and B.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #697000 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=697000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Were they disjoint events, there would be no probability for p(A+B).  So they aren't disjoint.<BR>\n" );
document.write( "If they were dependent, p(A and B) would not be= p(A)*p(B); stated another way, if they were independent, the joint probability would be the product of the separate probabilities.<BR>\n" );
document.write( "The joint probability is almost that, but it is a little more, 0.3834; therefore, the two are not independent, so there must be dependence. </SPAN>\n" );
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