document.write( "Question 1082998: Solve the equation for 0≤x≤2pi. Write your answer as a multiple of pi if possible.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"cot%5E2%28pi%2F2-%28x%29%29\" = sec(x) + 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thanks! \n" ); document.write( "
Algebra.Com's Answer #696993 by Edwin McCravy(20063)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\"cot%5E2%28pi%2F2-%28x%29%29+=+sec%28x%29+%2B+1\"\r\n" );
document.write( "\r\n" );
document.write( "Since \"pi%2F2-%28x%29\" is the complement of x,\r\n" );
document.write( "\r\n" );
document.write( "\"cot%28pi%2F2-%28x%29%29=tan%28x%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"tan%5E2%28x%29+=+sec%28x%29+%2B+1\"\r\n" );
document.write( "\r\n" );
document.write( "Since \"1%2Btan%5E2%28theta%29=sec%5E2%28theta%29\", \"tan%5E2%28theta%29=sec%5E2%28theta%29-1\" \r\n" );
document.write( "\r\n" );
document.write( "\"sec%5E2%28x%29-1=sec%28x%29%2B1\"\r\n" );
document.write( "\r\n" );
document.write( "\"sec%5E2%28x%29-sec%28x%29-2=0\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28sec%28x%29%5E%22%22-2%29%28sec%28x%29%5E%22%22%2B1%29=0\"\r\n" );
document.write( "\r\n" );
document.write( "\"sec%28x%29-2=0\",  \"sec%28x%29%2B1=0\"\r\n" );
document.write( "\r\n" );
document.write( "\"sec%28x%29=2\",  \"sec%28x%29=-1\"\r\n" );
document.write( "\r\n" );
document.write( "For \"sec%28x%29=2\" using the unit circle,\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C5%2C%0D%0A%0D%0Ax%2C%22%22=%22%22%2Cpi%2F3%2C+%22%2C%22%2C5pi%2F3%29\"\r\n" );
document.write( "\r\n" );
document.write( "For \"sec%28x%29=-1\" using the unit circle,\r\n" );
document.write( "\r\n" );
document.write( "\"matrix%281%2C3%2Cx%2C%22%22=%22%22%2Cpi%29\"\r\n" );
document.write( "\r\n" );
document.write( "Three solutions.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );