document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082939>Question 1082939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The surface area of a sphere, initially zero increase uniformly at the rate of 26 sq. cm per second. Find the rate at which the radius is increasing at then end of 2 seconds?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696992 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The surface area of a sphere, initially zero increase uniformly at the rate of 26 sq. cm per second. Find the rate at which the radius is increasing at then end of 2 seconds?<BR>\n" );
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document.write( "\"initially zero\" is not relevant.<BR>\n" );
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document.write( "SA = 4pi*r^2<BR>\n" );
document.write( "Differentiate wrt t.<BR>\n" );
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document.write( "dSA/dt = 8pi*r((dr/dt)<BR>\n" );
document.write( "8pi*dr/dt = 26<BR>\n" );
document.write( "dr/dt = 13/(4pi) cm/sec at 2 seconds.<BR>\n" );
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document.write( "Not clear what \"the end of 2 seconds\" means.\r<BR>\n" );
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