document.write( "Question 1082987: Suppose that ABC is a right triangle with right angle at B. If AC = 25 and the altitude BD = 20, what is AD? Answer and explain please.
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Algebra.Com's Answer #696967 by Edwin McCravy(20060)\"\" \"About 
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document.write( "Here is a triangle drawn to scale with AC = 25, and BD = 20.  \r\n" );
document.write( "But as you see, it cannot have a right angle at B.  The\r\n" );
document.write( "altitude BD = 20 is just too long to have a right angle at B.\r\n" );
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document.write( "Here is a triangle also drawn with he same AC = 25 as the\r\n" );
document.write( "first that has a right angle at B.  However the altitude\r\n" );
document.write( "is only about 12.2, not 20.\r\n" );
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document.write( "This makes us believe that it is impossible to have such a\r\n" );
document.write( "triangle.\r\n" );
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document.write( "To show that it is impossible, let's suppose that the altitude\r\n" );
document.write( "BD is actually 20 and angle B is a right angle. Let DC = x, then\r\n" );
document.write( "AD will = 25-x.\r\n" );
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document.write( "Then triangle ADB is similar to triangle BDC, so\r\n" );
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document.write( "\"AD%2F%22BD%22=BD%2F%22DC%22\"\r\n" );
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document.write( "\"%2825-x%29%2F20=20%2Fx\"\r\n" );
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document.write( "Cross-multiplying:\r\n" );
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document.write( "\"25x-x%5E2=400\"\r\n" );
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document.write( "\"-x%5E2%2B25x-400=0\"\r\n" );
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document.write( "\"x%5E2-25x%2B400=0\"\r\n" );
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document.write( "However this quadratic has no real solutions,\r\n" );
document.write( "because its discriminant is negative:\r\n" );
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document.write( "\"b%5E2-4ac=%28-25%29%5E2-4%281%29%28400%29=625-1600=-975\"\r\n" );
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document.write( "Therefore we have proved that there is no such triangle.\r\n" );
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document.write( "Edwin
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